Optimal. Leaf size=357 \[ -\frac{\sqrt{3} (B+i A) \tan ^{-1}\left (\frac{1+\frac{2 \sqrt [3]{a+b \tan (c+d x)}}{\sqrt [3]{a-i b}}}{\sqrt{3}}\right )}{2 d (a-i b)^{2/3}}+\frac{\sqrt{3} (-B+i A) \tan ^{-1}\left (\frac{1+\frac{2 \sqrt [3]{a+b \tan (c+d x)}}{\sqrt [3]{a+i b}}}{\sqrt{3}}\right )}{2 d (a+i b)^{2/3}}+\frac{3 (B+i A) \log \left (-\sqrt [3]{a+b \tan (c+d x)}+\sqrt [3]{a-i b}\right )}{4 d (a-i b)^{2/3}}-\frac{3 (-B+i A) \log \left (-\sqrt [3]{a+b \tan (c+d x)}+\sqrt [3]{a+i b}\right )}{4 d (a+i b)^{2/3}}-\frac{(-B+i A) \log (\cos (c+d x))}{4 d (a+i b)^{2/3}}+\frac{(B+i A) \log (\cos (c+d x))}{4 d (a-i b)^{2/3}}-\frac{x (A-i B)}{4 (a-i b)^{2/3}}-\frac{x (A+i B)}{4 (a+i b)^{2/3}} \]
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Rubi [A] time = 0.283826, antiderivative size = 357, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 6, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.24, Rules used = {3539, 3537, 57, 617, 204, 31} \[ -\frac{\sqrt{3} (B+i A) \tan ^{-1}\left (\frac{1+\frac{2 \sqrt [3]{a+b \tan (c+d x)}}{\sqrt [3]{a-i b}}}{\sqrt{3}}\right )}{2 d (a-i b)^{2/3}}+\frac{\sqrt{3} (-B+i A) \tan ^{-1}\left (\frac{1+\frac{2 \sqrt [3]{a+b \tan (c+d x)}}{\sqrt [3]{a+i b}}}{\sqrt{3}}\right )}{2 d (a+i b)^{2/3}}+\frac{3 (B+i A) \log \left (-\sqrt [3]{a+b \tan (c+d x)}+\sqrt [3]{a-i b}\right )}{4 d (a-i b)^{2/3}}-\frac{3 (-B+i A) \log \left (-\sqrt [3]{a+b \tan (c+d x)}+\sqrt [3]{a+i b}\right )}{4 d (a+i b)^{2/3}}-\frac{(-B+i A) \log (\cos (c+d x))}{4 d (a+i b)^{2/3}}+\frac{(B+i A) \log (\cos (c+d x))}{4 d (a-i b)^{2/3}}-\frac{x (A-i B)}{4 (a-i b)^{2/3}}-\frac{x (A+i B)}{4 (a+i b)^{2/3}} \]
Antiderivative was successfully verified.
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Rule 3539
Rule 3537
Rule 57
Rule 617
Rule 204
Rule 31
Rubi steps
\begin{align*} \int \frac{A+B \tan (c+d x)}{(a+b \tan (c+d x))^{2/3}} \, dx &=\frac{1}{2} (A-i B) \int \frac{1+i \tan (c+d x)}{(a+b \tan (c+d x))^{2/3}} \, dx+\frac{1}{2} (A+i B) \int \frac{1-i \tan (c+d x)}{(a+b \tan (c+d x))^{2/3}} \, dx\\ &=-\frac{(i A-B) \operatorname{Subst}\left (\int \frac{1}{(-1+x) (a+i b x)^{2/3}} \, dx,x,-i \tan (c+d x)\right )}{2 d}+\frac{(i A+B) \operatorname{Subst}\left (\int \frac{1}{(-1+x) (a-i b x)^{2/3}} \, dx,x,i \tan (c+d x)\right )}{2 d}\\ &=-\frac{(A-i B) x}{4 (a-i b)^{2/3}}-\frac{(A+i B) x}{4 (a+i b)^{2/3}}-\frac{(i A-B) \log (\cos (c+d x))}{4 (a+i b)^{2/3} d}+\frac{(i A+B) \log (\cos (c+d x))}{4 (a-i b)^{2/3} d}+\frac{(3 (i A-B)) \operatorname{Subst}\left (\int \frac{1}{\sqrt [3]{a+i b}-x} \, dx,x,\sqrt [3]{a+b \tan (c+d x)}\right )}{4 (a+i b)^{2/3} d}+\frac{(3 (i A-B)) \operatorname{Subst}\left (\int \frac{1}{(a+i b)^{2/3}+\sqrt [3]{a+i b} x+x^2} \, dx,x,\sqrt [3]{a+b \tan (c+d x)}\right )}{4 \sqrt [3]{a+i b} d}-\frac{(3 (i A+B)) \operatorname{Subst}\left (\int \frac{1}{\sqrt [3]{a-i b}-x} \, dx,x,\sqrt [3]{a+b \tan (c+d x)}\right )}{4 (a-i b)^{2/3} d}-\frac{(3 (i A+B)) \operatorname{Subst}\left (\int \frac{1}{(a-i b)^{2/3}+\sqrt [3]{a-i b} x+x^2} \, dx,x,\sqrt [3]{a+b \tan (c+d x)}\right )}{4 \sqrt [3]{a-i b} d}\\ &=-\frac{(A-i B) x}{4 (a-i b)^{2/3}}-\frac{(A+i B) x}{4 (a+i b)^{2/3}}-\frac{(i A-B) \log (\cos (c+d x))}{4 (a+i b)^{2/3} d}+\frac{(i A+B) \log (\cos (c+d x))}{4 (a-i b)^{2/3} d}+\frac{3 (i A+B) \log \left (\sqrt [3]{a-i b}-\sqrt [3]{a+b \tan (c+d x)}\right )}{4 (a-i b)^{2/3} d}-\frac{3 (i A-B) \log \left (\sqrt [3]{a+i b}-\sqrt [3]{a+b \tan (c+d x)}\right )}{4 (a+i b)^{2/3} d}-\frac{(3 (i A-B)) \operatorname{Subst}\left (\int \frac{1}{-3-x^2} \, dx,x,1+\frac{2 \sqrt [3]{a+b \tan (c+d x)}}{\sqrt [3]{a+i b}}\right )}{2 (a+i b)^{2/3} d}+\frac{(3 (i A+B)) \operatorname{Subst}\left (\int \frac{1}{-3-x^2} \, dx,x,1+\frac{2 \sqrt [3]{a+b \tan (c+d x)}}{\sqrt [3]{a-i b}}\right )}{2 (a-i b)^{2/3} d}\\ &=-\frac{(A-i B) x}{4 (a-i b)^{2/3}}-\frac{(A+i B) x}{4 (a+i b)^{2/3}}-\frac{\sqrt{3} (i A+B) \tan ^{-1}\left (\frac{1+\frac{2 \sqrt [3]{a+b \tan (c+d x)}}{\sqrt [3]{a-i b}}}{\sqrt{3}}\right )}{2 (a-i b)^{2/3} d}+\frac{\sqrt{3} (i A-B) \tan ^{-1}\left (\frac{1+\frac{2 \sqrt [3]{a+b \tan (c+d x)}}{\sqrt [3]{a+i b}}}{\sqrt{3}}\right )}{2 (a+i b)^{2/3} d}-\frac{(i A-B) \log (\cos (c+d x))}{4 (a+i b)^{2/3} d}+\frac{(i A+B) \log (\cos (c+d x))}{4 (a-i b)^{2/3} d}+\frac{3 (i A+B) \log \left (\sqrt [3]{a-i b}-\sqrt [3]{a+b \tan (c+d x)}\right )}{4 (a-i b)^{2/3} d}-\frac{3 (i A-B) \log \left (\sqrt [3]{a+i b}-\sqrt [3]{a+b \tan (c+d x)}\right )}{4 (a+i b)^{2/3} d}\\ \end{align*}
Mathematica [A] time = 0.241855, size = 305, normalized size = 0.85 \[ \frac{i \left (\frac{(A+i B) \left (2 \sqrt{3} \tan ^{-1}\left (\frac{1+\frac{2 \sqrt [3]{a+b \tan (c+d x)}}{\sqrt [3]{a+i b}}}{\sqrt{3}}\right )-2 \log \left (-\sqrt [3]{a+b \tan (c+d x)}+\sqrt [3]{a+i b}\right )+\log \left (\sqrt [3]{a+i b} \sqrt [3]{a+b \tan (c+d x)}+(a+b \tan (c+d x))^{2/3}+(a+i b)^{2/3}\right )\right )}{(a+i b)^{2/3}}-\frac{(A-i B) \left (2 \sqrt{3} \tan ^{-1}\left (\frac{1+\frac{2 \sqrt [3]{a+b \tan (c+d x)}}{\sqrt [3]{a-i b}}}{\sqrt{3}}\right )-2 \log \left (-\sqrt [3]{a+b \tan (c+d x)}+\sqrt [3]{a-i b}\right )+\log \left (\sqrt [3]{a-i b} \sqrt [3]{a+b \tan (c+d x)}+(a+b \tan (c+d x))^{2/3}+(a-i b)^{2/3}\right )\right )}{(a-i b)^{2/3}}\right )}{4 d} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.083, size = 69, normalized size = 0.2 \begin{align*}{\frac{1}{2\,d}\sum _{{\it \_R}={\it RootOf} \left ({{\it \_Z}}^{6}-2\,{{\it \_Z}}^{3}a+{a}^{2}+{b}^{2} \right ) }{\frac{B{{\it \_R}}^{3}+Ab-aB}{{{\it \_R}}^{5}-{{\it \_R}}^{2}a}\ln \left ( \sqrt [3]{a+b\tan \left ( dx+c \right ) }-{\it \_R} \right ) }} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{B \tan \left (d x + c\right ) + A}{{\left (b \tan \left (d x + c\right ) + a\right )}^{\frac{2}{3}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{A + B \tan{\left (c + d x \right )}}{\left (a + b \tan{\left (c + d x \right )}\right )^{\frac{2}{3}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 21.3712, size = 215, normalized size = 0.6 \begin{align*} \left (\frac{i \, A^{3} - 3 \, A^{2} B - 3 i \, A B^{2} + B^{3}}{8 \, a^{2} d^{3} + 16 i \, a b d^{3} - 8 \, b^{2} d^{3}}\right )^{\frac{1}{3}} \log \left ({\left (b \tan \left (d x + c\right ) + a\right )}^{\frac{1}{3}} d - i \,{\left (i \, a - b\right )}^{\frac{1}{3}} d\right ) + \left (\frac{-i \, A^{3} - 3 \, A^{2} B + 3 i \, A B^{2} + B^{3}}{8 \, a^{2} d^{3} - 16 i \, a b d^{3} - 8 \, b^{2} d^{3}}\right )^{\frac{1}{3}} \log \left ({\left (b \tan \left (d x + c\right ) + a\right )}^{\frac{1}{3}} d + i \,{\left (-i \, a - b\right )}^{\frac{1}{3}} d\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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